A force of 2.45 N is applied to an object on a horizontal surface that causes it to move horizontally through a distance of 1.73 m. Correct to three significant figures, the total work done on the object is J.
Question
A force of 2.45 N is applied to an object on a horizontal surface that causes it to move horizontally through a distance of 1.73 m. Correct to three significant figures, the total work done on the object is J.
Solution
The work done on an object is calculated by the formula:
Work = Force x Distance
Given in the problem, the force (F) is 2.45 N and the distance (d) is 1.73 m.
Substituting these values into the formula gives:
Work = 2.45 N x 1.73 m = 4.24 J
So, the total work done on the object is 4.24 J, correct to three significant figures.
Similar Questions
When a force of 15 N is applied horizontally to an object, causing the object to move a horizontal distance of 3.0 m, how much work is done on the object?Multiple choice question.18 J5.0 J45 J0.20 J
A mass of 8 kg is traveling at a constant 10.4 m/s when a 38 N force, F, starts to act in the opposite direction, stopping the object after it has traveled. How much work was done by the force, F, in stopping the object?
6 kJ of work is done by a force in moving an object uniformly through 120 m in 1 minute. The force applied is:a.720 Nb.20 Nc.50 Nd.12 N
How much work do you need to do if you use a force of 3 Newtons to move a table 25 meters?75 meters per second squared0.12 N-m0.12 meter per second squared75 N-m
A force of 90 N moves a sledge a distance of 15 m. Enter the symbol equation you would use to calculate the work done by this force.
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.