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When maltose is enzymatically hydrolysed (a) hemiacetal formation takes place (b) itundergoes epimerization (c) -D-glucose and -D glucose are liberated (d) -D-glucose and -D fructose are liberated.

Question

When maltose is enzymatically hydrolysed (a) hemiacetal formation takes place (b) itundergoes epimerization (c) -D-glucose and -D glucose are liberated (d) -D-glucose and -D fructose are liberated.

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Solution

When maltose is enzymatically hydrolyzed, it breaks down into two molecules of α-D-glucose. So, the correct answer is (d) α-D-glucose and β-D fructose are liberated.

Here's the step-by-step process:

  1. Maltose, a disaccharide, is composed of two units of glucose joined by an α(1→4) glycosidic linkage.

  2. When maltose is hydrolyzed, it means that it is broken down by the addition of water. This process is catalyzed by the enzyme maltase.

  3. The water molecule breaks the glycosidic bond, splitting the maltose into two separate glucose molecules.

  4. These glucose molecules are both in the α-D-glucose form, not β-D-glucose or β-D fructose.

So, the statements (a) hemiacetal formation takes place and (b) it undergoes epimerization are not correct in this context. Hemiacetal formation and epimerization are processes that involve the conversion of one type of molecule into another, which is not what happens when maltose is hydrolyzed.

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