def func(a): i=a while(i >= 1): if i%2==0: print("breaking", end = " ") break else: print(i, end = " ") i=i-1 return i print(func(9))
Question
def func(a): i=a while(i >= 1): if i%2==0: print("breaking", end = " ") break else: print(i, end = " ") i=i-1 return i print(func(9))
Solution
The given code is written in Python. Here's a step-by-step explanation of what it does:
-
The function
funcis defined with one parametera. -
Inside the function, a variable
iis initialized with the value ofa. -
A
whileloop is started which will continue as long asiis greater than or equal to 1. -
Inside the loop, an
ifcondition checks ifiis divisible by 2 (i.e.,iis an even number). If it is, it prints "breaking" and then breaks the loop. -
If
iis not divisible by 2 (i.e.,iis an odd number), it prints the value ofiand then decreasesiby 1. -
This process continues until
ibecomes less than 1 or an even number is encountered. -
Finally, the function returns the last value of
i. -
The function
funcis called with the argument 9 and the returned value is printed.
So, when you run this code, it will print "9 7 5 3 breaking" and then print "2", which is the returned value from the function.
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