To solve this problem, we need to find the z-score that corresponds to the 96th percentile of a normal distribution, and then convert this z-score to a weight in kilograms using the given mean and standard deviation.

1. The z-score corresponding to the 96th percentile of a normal distribution is approximately 1.75. This value can be found using a standard normal distribution table or a calculator with a normal distribution function.

2. The standard deviation is the square root of the variance, so the standard deviation of the birth weights is sqrt(36) = 6 kg.

3. The weight corresponding to a z-score of 1.75 is given by the formula weight = mean + z-score * standard deviation. Substituting the given values, we get weight = 26 + 1.75 * 6 = 36.5 kg.

So, the lightest weight of the heaviest 96% of newly born baby buffalos is 36.5 kg. Since the question asks for the answer without units, the answer is 36.5.

Question

To solve this problem, we need to find the z-score that corresponds to the 96th percentile of a normal distribution, and then convert this z-score to a weight in kilograms using the given mean and standard deviation.

1. The z-score corresponding to the 96th percentile of a normal distribution is approximately 1.75. This value can be found using a standard normal distribution table or a calculator with a normal distribution function.

2. The standard deviation is the square root of the variance, so the standard deviation of the birth weights is sqrt(36) = 6 kg.

3. The weight corresponding to a z-score of 1.75 is given by the formula weight = mean + z-score * standard deviation. Substituting the given values, we get weight = 26 + 1.75 * 6 = 36.5 kg.

So, the lightest weight of the heaviest 96% of newly born baby buffalos is 36.5 kg. Since the question asks for the answer without units, the answer is 36.5.

Knowee AI · Accepted Answer

To solve this problem, we need to find the z-score that corresponds to the 96th percentile of a normal distribution, and then convert this z-score to a weight in kilograms using the given mean and standard deviation.

1. The z-score corresponding to the 96th percentile of a normal distribution is approximately 1.75. This value can be found using a standard normal distribution table or a calculator with a normal distribution function.

2. The standard deviation is the square root of the variance, so the standard deviation of the birth weights is sqrt(36) = 6 kg.

3. The weight corresponding to a z-score of 1.75 is given by the formula weight = mean + z-score * standard deviation. Substituting the given values, we get weight = 26 + 1.75 * 6 = 36.5 kg.

So, the lightest weight of the heaviest 96% of newly born baby buffalos is 36.5 kg. Since the question asks for the answer without units, the answer is 36.5.

The birth weight (in kg) of a particular species of buffalo is normally distributed with mean 26 and variance 36.Find the lightest weight of the heaviest 96% of newly born baby buffalos. Do not include any units in your answer.

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