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A toy car travels on a circular track at a constant speed of 0.50 m s –1. It passes a point on thetrack at time t = 0 and takes a time of 40 s to travel once around the track.The magnitude of the average velocity of the car between t = 0 and t = 20 s is v20.The magnitude of the average velocity of the car between t = 0 and t = 40 s is v40.What are v20 and v40?v20 / m s –1 v40 / m s –1A 0.32 0B 0.32 0.32C 0.50 0D 0.50 0.50

Question

A toy car travels on a circular track at a constant speed of 0.50 m s –1. It passes a point on thetrack at time t = 0 and takes a time of 40 s to travel once around the track.The magnitude of the average velocity of the car between t = 0 and t = 20 s is v20.The magnitude of the average velocity of the car between t = 0 and t = 40 s is v40.What are v20 and v40?v20 / m s –1 v40 / m s –1A 0.32 0B 0.32 0.32C 0.50 0D 0.50 0.50

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Solution

The average velocity of an object moving in a circular path is zero when it completes one full round because the displacement is zero (it comes back to the starting point).

Given that the toy car takes 40 seconds to complete one round, the average velocity v40 at t=40s is 0 m/s.

However, at t=20s, the car is at the opposite point on the circular track. The displacement is equal to the diameter of the circle. But we don't have the radius of the circle, so we can't calculate the exact value of v20. But we know that it's not zero (because there is displacement) and it's not 0.50 m/s (because the speed is constant and the car hasn't completed a full round yet).

So, the answer is A: v20 = 0.32 m/s and v40 = 0 m/s.

This problem has been solved

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