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Chemistry I15) What is the volume occupied by 1.24 mol of a gas at 35C if the pressure is 96.2 kPa? 31.0 L 37.0 L 33.0 L 36.0 LPrevious Question Next QuestionDo not use the 'Forward' or 'Back' button on your browser.

Question

Chemistry I15) What is the volume occupied by 1.24 mol of a gas at 35C if the pressure is 96.2 kPa? 31.0 L 37.0 L 33.0 L 36.0 LPrevious Question Next QuestionDo not use the 'Forward' or 'Back' button on your browser.

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Solution

To solve this problem, we can use the ideal gas law equation, which is PV = nRT.

Where: P = pressure V = volume n = number of moles R = ideal gas constant T = temperature

Given: P = 96.2 kPa n = 1.24 mol T = 35°C = 308.15 K (converted from Celsius to Kelvin by adding 273.15) R = 8.3145 L·kPa/(K·mol) (this is the value of R in these units)

We need to solve for V (volume).

Rearranging the equation to solve for V gives us V = nRT/P.

Substituting the given values into the equation gives us V = (1.24 mol * 8.3145 L·kPa/(K·mol) * 308.15 K) / 96.2 kPa.

Solving this gives us V ≈ 33.0 L.

So, the volume occupied by 1.24 mol of a gas at 35C and 96.2 kPa is approximately 33.0 L.

This problem has been solved

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