To solve this problem, we first need to convert the lengths of the ants from cm to mm, because the speeds are given in mm/sec.

1 cm = 10 mm, so the first ant is 10 mm long.
1.2 cm = 12 mm, so the second ant is 12 mm long.

The total distance they need to cross is the sum of their lengths, which is 10 mm + 12 mm = 22 mm.

The ants are moving in opposite directions, so their speeds add up. The total speed is 2 mm/sec + 3 mm/sec = 5 mm/sec.

The time it takes for them to cross each other is the total distance divided by the total speed.

So, the time = 22 mm / 5 mm/sec = 4.4 seconds.

Therefore, the ants will take 4.4 seconds to cross each other.

Question

To solve this problem, we first need to convert the lengths of the ants from cm to mm, because the speeds are given in mm/sec.

1 cm = 10 mm, so the first ant is 10 mm long.
1.2 cm = 12 mm, so the second ant is 12 mm long.

The total distance they need to cross is the sum of their lengths, which is 10 mm + 12 mm = 22 mm.

The ants are moving in opposite directions, so their speeds add up. The total speed is 2 mm/sec + 3 mm/sec = 5 mm/sec.

The time it takes for them to cross each other is the total distance divided by the total speed.

So, the time = 22 mm / 5 mm/sec = 4.4 seconds.

Therefore, the ants will take 4.4 seconds to cross each other.

Knowee AI · Accepted Answer

To solve this problem, we first need to convert the lengths of the ants from cm to mm, because the speeds are given in mm/sec.

1 cm = 10 mm, so the first ant is 10 mm long.
1.2 cm = 12 mm, so the second ant is 12 mm long.

The total distance they need to cross is the sum of their lengths, which is 10 mm + 12 mm = 22 mm.

The ants are moving in opposite directions, so their speeds add up. The total speed is 2 mm/sec + 3 mm/sec = 5 mm/sec.

The time it takes for them to cross each other is the total distance divided by the total speed.

So, the time = 22 mm / 5 mm/sec = 4.4 seconds.

Therefore, the ants will take 4.4 seconds to cross each other.

Two ants of lengths 1 cm and 1.2 cm crawl in opposite directions with average speeds 2 and 3 mm per second respectively. How many seconds will they take to cross each other?