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A man walks from point A to B at an average speed of 1.0 m/sand immediately returns at an average speed of 1.5 ms-1 .What is theaverage speed for the round trip?A. 0.33 m/sB. 1.20 m/sC. 1.25 m/sD. 2.50 m/s

Question

A man walks from point A to B at an average speed of 1.0 m/sand immediately returns at an average speed of 1.5 ms-1 .What is theaverage speed for the round trip?A. 0.33 m/sB. 1.20 m/sC. 1.25 m/sD. 2.50 m/s

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Solution

The average speed for a round trip is calculated by dividing the total distance by the total time.

Let's assume the distance between point A and B is d (it doesn't matter what the actual distance is, as it will cancel out in the calculation).

  1. The time taken to go from A to B at a speed of 1.0 m/s is d/1.0 = d seconds.
  2. The time taken to return from B to A at a speed of 1.5 m/s is d/1.5 = 2d/3 seconds.

So, the total time for the round trip is d + 2d/3 = 5d/3 seconds.

The total distance for the round trip is 2d (d to go from A to B and d to return from B to A).

Therefore, the average speed for the round trip is total distance / total time = 2d / (5d/3) = 1.2 m/s.

So, the correct answer is B. 1.20 m/s.

This problem has been solved

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