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What will be the output of the following code?        python    class Shape:        def area(self):            pass    class Circle(Shape):        def __init__(self, radius):            self.radius = radius        def area(self):            return 3.14 * self.radius * self.radius    class Square(Shape):        def __init__(self, side):            self.side = side        def area(self):            return self.side * self.side    shapes = [Circle(2), Square(3)]    for shape in shapes:        print(shape.area())3.14\n33.14\n912.56\n912.56\n3

Question

What will be the output of the following code?        python    class Shape:        def area(self):            pass    class Circle(Shape):        def init(self, radius):            self.radius = radius        def area(self):            return 3.14 * self.radius * self.radius    class Square(Shape):        def init(self, side):            self.side = side        def area(self):            return self.side * self.side    shapes = [Circle(2), Square(3)]    for shape in shapes:        print(shape.area())3.14\n33.14\n912.56\n912.56\n3

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Solution 1

The output of the code will be:

12.56 9

Explanation:

The code defines a list of shapes, where each shape is an instance of either the Circle or Square class. Both of these classes inherit from the Shape class and override the area method.

The Circle's area method calculates the area of a circle, which is πr². For a circle with a radius of 2, the area is 3.14 * 2 * 2 = 12.56.

The Square's area method calculates the area of a square, which is side². For a square with a side length of 3, the area is 3 * 3 = 9.

The for loop iterates over each shape in the list and prints the result of the shape's area method. Therefore, the output of the code is 12.56 (the area of the circle) followed by 9 (the area of the square).

This problem has been solved

Solution 2

The output of the code will be:

12.56 9

Explanation:

The code defines a base class Shape with a method area that does nothing. Then it defines two subclasses Circle and Square that each have their own implementation of the area method.

The Circle class calculates the area of a circle using the formula πr², where r is the radius of the circle. The Square class calculates the area of a square using the formula s², where s is the side length of the square.

The code then creates a list of two shapes: a circle with radius 2 and a square with side length 3. It iterates over this list and prints the area of each shape.

The area of the circle is 3.14 * 2 * 2 = 12.56. The area of the square is 3 * 3 = 9.

This problem has been solved

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