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What will be the output of the following Python code?class objects: def __init__(self): self.colour = None self._shape = "Circle"   def display(self, s): self._shape = sobj=objects()print(obj._objects_shape)The program runs fine because name mangling has been properly implementedError because the member shape is a protected memberError because the proper syntax for name mangling hasn’t been implementedError because the member shape is a private member

Question

What will be the output of the following Python code?class objects: def init(self): self.colour = None self._shape = "Circle"   def display(self, s): self._shape = sobj=objects()print(obj._objects_shape)The program runs fine because name mangling has been properly implementedError because the member shape is a protected memberError because the proper syntax for name mangling hasn’t been implementedError because the member shape is a private member

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Solution

The output of the Python code will be an error because the proper syntax for name mangling hasn’t been implemented.

In Python, name mangling is used for variables that are meant to be private to a class and it is implemented by prefixing the variable name with double underscore "__". In the given code, the variable '_shape' is prefixed with a single underscore, which is a convention for indicating that a variable or method is intended for internal use within the class (it's a protected member), but it doesn't actually prevent access to it.

However, the print statement is trying to access '_objects_shape' which is not defined. If it was trying to access the '_shape' variable, it should have been written as 'print(obj._shape)'.

So, the error is due to the incorrect variable name being accessed, not because of the lack of name mangling.

This problem has been solved

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