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What will be the output of the following Python code? class student: def __init__(self): self.marks = 97 self.__cgpa = 8.7 def display(self): print(self.marks)obj=student()print(obj._student__cgpa) The program runs fine and 8.7 is printed Error because private class members can’t be accessed Error because the proper syntax for name mangling hasn’t been implemented The program runs fine but nothing is printedClear ResponseSave & Next

Question

What will be the output of the following Python code? class student: def init(self): self.marks = 97 self.__cgpa = 8.7 def display(self): print(self.marks)obj=student()print(obj._student__cgpa) The program runs fine and 8.7 is printed Error because private class members can’t be accessed Error because the proper syntax for name mangling hasn’t been implemented The program runs fine but nothing is printedClear ResponseSave & Next

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Solution 1

The program runs fine and 8.7 is printed.

Here's the step by step explanation:

  1. A class named 'student' is defined with two attributes: 'marks' and '__cgpa'. The 'marks' attribute is public, while '__cgpa' is private due to the double underscore prefix.

  2. The 'display' method is defined to print the 'marks' attribute.

  3. An object 'obj' of the 'student' class is created.

  4. The private attribute '__cgpa' is accessed using name mangling, which is a technique used in Python for accessing private attributes. The syntax for this is '_classname__attributename'. In this case, it is '_student__cgpa'.

  5. The value of '__cgpa' (8.7) is printed.

So, the output of the code will be '8.7'.

This problem has been solved

Solution 2

The program runs fine and 8.7 is printed.

Here's the step by step explanation:

  1. A class named 'student' is defined with two attributes: 'marks' and '__cgpa'. The double underscore before 'cgpa' makes it a private attribute.

  2. A method named 'display' is defined within the class that prints the value of 'marks'.

  3. An object 'obj' of the class 'student' is created.

  4. The private attribute '__cgpa' is accessed using name mangling, which is a technique used in Python for accessing private attributes. The syntax for this is '_classname__attributename'.

  5. So, 'print(obj._student__cgpa)' prints the value of '__cgpa', which is 8.7.

Therefore, the output of the code will be 8.7.

This problem has been solved

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