Given pointer to a node X in a singly linked list. Only one pointer is given, pointer to head node is not given, can we delete the node X from given linked list?

No, we cannot delete a node X from a singly linked list using only a pointer to that node. The reason is that deletion requires a pointer to the previous node, and in a singly linked list, we cannot traverse backwards.

However, there is a trick to delete the node if we are given a pointer to the node and we know that the node is not the last node of the list. The trick is to copy the data from the next node into the node to be deleted and then to delete the next node.

Here are the steps:

1. Store the next node of the given node in a pointer.
2. Copy the data of the next node to the data of the current node.
3. Now, take the next of the next node and link it to the current node.
4. Finally, delete the next node.

This solution doesn't work if the node to be deleted is the last node in the list. That's because there is no next node to copy the data from.

No, we cannot delete a node X from a singly linked list using only a pointer to node X. This is because deletion requires a pointer to the previous node, and in a singly linked list, we cannot traverse backwards.

However, there is a trick to delete the node if we are given a pointer to the node. The trick is to copy the data from the next node to the node to be deleted and to delete the next node. But this trick won't work if the node to be deleted is the last node in the list. That's why the standard practice is to always have a pointer to the head node.

No, we cannot delete a node X from a singly linked list using only a pointer to that node. The reason is that deletion requires a pointer to the previous node, and in a singly linked list, we cannot traverse backwards.

However, there is a trick to delete the node if the node to be deleted is not the last node of the list. We can copy the data of the next node to the node to be deleted and delete the next node. But this solution doesn't work if the node to be deleted is the last node. That's why, in a singly linked list, we need at least one pointer to a node before the node to be deleted.

No, we cannot delete a node X from a singly linked list using only a pointer to that node. The reason is that deletion requires a pointer to the previous node, and in a singly linked list, we cannot traverse backwards.

However, there is a trick to delete the node if we are given a pointer to the node and we know that the node is not the last node of the list. The trick is to copy the data from the next node into the node to be deleted and to delete the next node.

Here are the steps:

1. Store the next node of the given node in a pointer say 'temp'.
2. Copy the data of 'temp' to the given node (node to be deleted).
3. Then change the next of given node to temp->next.
4. Finally, delete 'temp'.

But this solution doesn’t work if the node to be deleted is the last node of the list. So, it's not a complete solution.

No, we cannot delete a node X from a singly linked list using only a pointer to that node. Here's why:

1. In a singly linked list, each node contains data and a pointer to the next node in the list.

2. To delete a node, we need to update the 'next' pointer of the previous node to point to the node after the one we want to delete.

3. However, in a singly linked list, we can't traverse backwards. If we only have a pointer to the node we want to delete, we don't have a way to access its previous node.

4. Therefore, without a pointer to the head node or the previous node, we can't delete a node from a singly linked list.

However, there is a workaround to this problem. We can't delete the node, but we can copy the data from the next node into the node we want to delete and then delete the next node. This will effectively remove the current node's data from the list. But this solution doesn't work if the node to be deleted is the last node in the list.