Given a doubly Linked list and a position. The task is to delete a node from a given position (position starts from 1) in a doubly linked list and return the head of the doubly Linked list.
Question
Given a doubly Linked list and a position. The task is to delete a node from a given position (position starts from 1) in a doubly linked list and return the head of the doubly Linked list.
Solution
Here is a step-by-step guide to delete a node from a given position in a doubly linked list:
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First, check if the head node itself is the node to be deleted. If the head node is to be deleted, change the head node to the next node. Make sure to set the previous pointer of the new head node to null. Return the new head node.
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Initialize a node pointer, start from the head node, and traverse the doubly linked list until the node to be deleted is found or the end of the list is reached. Keep track of the previous node while traversing.
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If the node to be deleted is found, check if it is the last node in the list. If it is the last node, change the next pointer of the previous node to null.
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If the node to be deleted is not the last node, then set the next pointer of the previous node to the next node of the node to be deleted and also set the previous pointer of the next node to the previous node of the node to be deleted.
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Finally, free the memory allocated for the node to be deleted.
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Return the head of the modified list.
This algorithm assumes that the position given is valid. If the position is not valid (i.e., it is greater than the number of nodes in the list), you should handle this case appropriately, for example by returning the original head node without making any modifications.
Similar Questions
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