What is the total number of atoms in 0.100 mol of [Pt(NH3)2Cl2]?

To find the total number of atoms in 0.100 mol of [Pt(NH3)2Cl2], you need to understand the molecular structure of the compound.

1. The compound [Pt(NH3)2Cl2] consists of 1 atom of Platinum (Pt), 2 atoms of Nitrogen (N), 6 atoms of Hydrogen (H), and 2 atoms of Chlorine (Cl).

2. Therefore, there are a total of 1 + 2 + 6 + 2 = 11 atoms in one molecule of [Pt(NH3)2Cl2].

3. Avogadro's number (6.022 x 10^23) tells us the number of entities (like atoms or molecules) in one mole of a substance.

4. So, in one mole of [Pt(NH3)2Cl2], there are 11 x (6.022 x 10^23) atoms.

5. Therefore, in 0.100 mol of [Pt(NH3)2Cl2], there are 0.100 x 11 x (6.022 x 10^23) atoms.

6. Doing the math, we find that there are approximately 6.6242 x 10^23 atoms in 0.100 mol of [Pt(NH3)2Cl2].