Total number of atoms present in 10ml of NH3 at NTP :
Question
Total number of atoms present in 10ml of NH3 at NTP :
Solution
To find the total number of atoms present in 10ml of NH3 at NTP, we need to follow these steps:
Step 1: Determine the molar mass of NH3. The molar mass of NH3 (ammonia) is calculated by adding up the atomic masses of its constituent elements. Nitrogen (N) has an atomic mass of 14.01 g/mol, and hydrogen (H) has an atomic mass of 1.01 g/mol. Since there are three hydrogen atoms in NH3, we multiply the atomic mass of hydrogen by 3. Therefore, the molar mass of NH3 is: (1.01 g/mol * 3) + 14.01 g/mol = 17.04 g/mol
Step 2: Convert the volume of NH3 from milliliters to liters. Since the molar mass is given in grams per mole, we need to convert the volume from milliliters to liters. There are 1000 milliliters in 1 liter, so 10 ml is equal to 10/1000 = 0.01 liters.
Step 3: Calculate the number of moles of NH3. To find the number of moles, we divide the given mass (in grams) by the molar mass (in grams per mole). Since we don't have the mass of NH3, we can use the volume and the density of NH3 at NTP (which is approximately 0.771 g/L) to calculate the mass. The mass of NH3 can be calculated as: mass = volume * density = 0.01 L * 0.771 g/L = 0.00771 g
Now, we can calculate the number of moles of NH3: moles = mass / molar mass = 0.00771 g / 17.04 g/mol ≈ 0.000452 moles
Step 4: Calculate the total number of atoms. Since there are three hydrogen atoms in one molecule of NH3, we need to multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mol) and by 3: total number of atoms = moles * Avogadro's number * 3 total number of atoms = 0.000452 moles * 6.022 x 10^23 atoms/mol * 3 ≈ 8.17 x 10^20 atoms
Therefore, the total number of atoms present in 10ml of NH3 at NTP is approximately 8.17 x 10^20 atoms.
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