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Select the correct answer What will be the output of the following Java code?class evaluate {  public static void main(String args[])     {   int arr[] = new int[] {0 , 1, 2, 3, 4, 5, 6, 7, 8, 9};   int n = 8;      n = arr[arr[n] / 4];   System.out.println(arr[n] / 4);    } }Options1230

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Select the correct answer What will be the output of the following Java code?class evaluate {  public static void main(String args[])     {   int arr[] = new int[] {0 , 1, 2, 3, 4, 5, 6, 7, 8, 9};   int n = 8;      n = arr[arr[n] / 4];   System.out.println(arr[n] / 4);    } }Options1230

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Solution

The output of the given Java code will be 1.

Here's the step-by-step explanation:

  1. An integer array 'arr' is declared and initialized with values from 0 to 9.
  2. An integer 'n' is declared and initialized with the value 8.
  3. The value of 'n' is updated to the value of the element at the index 'arr[n] / 4'. Here, 'arr[n]' is 'arr[8]' which is 8. So, 'n' becomes 'arr[8 / 4]' which is 'arr[2]'. The value at 'arr[2]' is 2. So, 'n' becomes 2.
  4. The value of 'arr[n] / 4' is printed. Here, 'arr[n]' is 'arr[2]' which is 2. So, 'arr[2] / 4' is 0.5. But since we are dealing with integers, the decimal part is truncated and the result is 0.

So, the output of the code will be 0.

This problem has been solved

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