The code is written in Java. It declares an array of integers and then prints out the elements of the array from the second element to the second last element. Here's a step-by-step explanation:

1. The array `arr` is declared and initialized with the values `{11, 21, 31, 41, 51}`.

2. A for loop is set up to iterate over the array. The loop variable `i` is initialized to 1, which is the second element in the array (since array indices start at 0 in Java).

3. The loop continues as long as `i` is less than `arr.length - 2`. The `length` property of an array in Java gives the number of elements in the array, so `arr.length - 2` is the index of the second last element in the array.

4. In each iteration of the loop, the `i`th element of the array is printed out, followed by a space.

5. The loop increments `i` by 1 in each iteration (`++i`).

So, the output of the code will be:

```
21
31
```

This is because the loop starts at the second element (21) and ends at the second last element (31). The first (11) and last two elements (41, 51) are not printed.

Question

The code is written in Java. It declares an array of integers and then prints out the elements of the array from the second element to the second last element. Here's a step-by-step explanation:

1. The array `arr` is declared and initialized with the values `{11, 21, 31, 41, 51}`.

2. A for loop is set up to iterate over the array. The loop variable `i` is initialized to 1, which is the second element in the array (since array indices start at 0 in Java).

3. The loop continues as long as `i` is less than `arr.length - 2`. The `length` property of an array in Java gives the number of elements in the array, so `arr.length - 2` is the index of the second last element in the array.

4. In each iteration of the loop, the `i`th element of the array is printed out, followed by a space.

5. The loop increments `i` by 1 in each iteration (`++i`).

So, the output of the code will be:

```
21 
31 
```

This is because the loop starts at the second element (21) and ends at the second last element (31). The first (11) and last two elements (41, 51) are not printed.

Knowee AI · Accepted Answer

The code is written in Java. It declares an array of integers and then prints out the elements of the array from the second element to the second last element. Here's a step-by-step explanation:

1. The array `arr` is declared and initialized with the values `{11, 21, 31, 41, 51}`.

2. A for loop is set up to iterate over the array. The loop variable `i` is initialized to 1, which is the second element in the array (since array indices start at 0 in Java).

3. The loop continues as long as `i` is less than `arr.length - 2`. The `length` property of an array in Java gives the number of elements in the array, so `arr.length - 2` is the index of the second last element in the array.

4. In each iteration of the loop, the `i`th element of the array is printed out, followed by a space.

5. The loop increments `i` by 1 in each iteration (`++i`).

So, the output of the code will be:

```
21 
31 
```

This is because the loop starts at the second element (21) and ends at the second last element (31). The first (11) and last two elements (41, 51) are not printed.

Find the output of the following code.class Output { public static void main(String args[]) { int arr[] = {11, 21, 31, 41, 51}; for ( int i = 1; i < arr.length - 2; ++i) System.out.println(arr[i] + " "); } }*11 21 31 4111 21 3121 3131 41 51

Question

Solution

Similar Questions

Upgrade your grade with Knowee