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The greatest number of four digits which is divisible by 15, 25, 40 and 75 is:

Question

The greatest number of four digits which is divisible by 15, 25, 40 and 75 is:

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Solution

To find the greatest number of four digits which is divisible by 15, 25, 40 and 75, we need to find the least common multiple (LCM) of these numbers first.

Step 1: Prime factorization of the numbers 15 = 3 * 5 25 = 5^2 40 = 2^3 * 5 75 = 3 * 5^2

Step 2: Find the LCM The LCM is the product of the highest powers of all the factors that appear in any of the numbers. So, LCM = 2^3 * 3 * 5^2 = 8 * 3 * 25 = 600

Step 3: Find the greatest 4-digit number divisible by the LCM The greatest 4-digit number is 9999. When we divide 9999 by 600, we get a quotient of 16 and a remainder of 399.

So, the greatest 4-digit number divisible by 600 is 9999 - 399 = 9600.

Therefore, the greatest number of four digits which is divisible by 15, 25, 40 and 75 is 9600.

This problem has been solved

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