The largest four digit number exactly divisible by each of 12, 15, 18 and 27 is:a.9720b.9930c.9960d.9690

To find the largest four-digit number that is exactly divisible by 12, 15, 18, and 27, we need to find the least common multiple (LCM) of these numbers.

Step 1: Prime factorization of each number

• 12 = 2^2 * 3
• 15 = 3 * 5
• 18 = 2 * 3^2
• 27 = 3^3

Step 2: Find the LCM The LCM is found by multiplying the highest power of all prime numbers in the factorization. So, LCM = 2^2 * 3^3 * 5 = 540

Step 3: Find the largest four-digit number divisible by the LCM The largest four-digit number is 9999. When we divide 9999 by 540, we get a quotient of 18 and a remainder of 459.

So, the largest four-digit number divisible by 540 is 9999 - 459 = 9540.

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