Three times the first of three consecutive odd integers is 3 more than twice the third. The third integer is

Let's denote the three consecutive odd integers as x, x+2, and x+4.

According to the problem, three times the first integer is 3 more than twice the third. We can write this as an equation:

3x = 2(x+4) + 3

Solving this equation will give us the value of x, which represents the first integer.

First, distribute the 2 on the right side of the equation:

3x = 2x + 8 + 3

Then, simplify the right side:

3x = 2x + 11

Next, subtract 2x from both sides to isolate x:

x = 11

So, the first integer is 11.

The third integer, then, is x+4, or 11+4, which equals 15.

Therefore, the third integer is 15.