The sum of three consecutive integers is 237237. Find the three integers.
Question
The sum of three consecutive integers is 237237. Find the three integers.
Solution
Let's denote the three consecutive integers as n, n+1, and n+2.
According to the problem, the sum of these three integers is 237237. So we can write the equation as:
n + (n+1) + (n+2) = 237237
This simplifies to:
3n + 3 = 237237
Subtract 3 from both sides:
3n = 237234
Divide both sides by 3:
n = 79078
So, the three consecutive integers are 79078, 79079, and 79080.
Similar Questions
The sum of three consecutive numbers is 357357.a.Use an equation to find the smallest of the three numbers.
The sum of three consecutive integers is 135. What is the smaller number?*45474644
The sum of three consecutive numbers is 21. What are the three numbers? write an equation and solve inverse operations.
The sum of three consecutive even numbers is 132. What is the smallest number?Options444842446
7. The sum of three consecutive multiples of 8 is 888. Find the multiples.Solution:
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.