7. The sum of three consecutive multiples of 8 is 888. Find the multiples.Solution:

Sure, here is the solution:

Let's denote the three consecutive multiples of 8 as 8n, 8(n+1), and 8(n+2). These are three consecutive multiples of 8 because they are separated by 8.

According to the problem, the sum of these three numbers is 888. So we can write the equation:

8n + 8(n+1) + 8(n+2) = 888

Simplify the equation:

8n + 8n + 8 + 8n + 16 = 888

Combine like terms:

24n + 24 = 888

Subtract 24 from both sides:

24n = 864

Divide both sides by 24:

n = 36

So the three consecutive multiples of 8 are 836 = 288, 837 = 296, and 8*38 = 304.