Calculate the solution to these simultaneous equations using the substitution method: (1)(1)2𝑦2y==𝑥+9x+9(2)(2)𝑦−3𝑥y−3x==33
Question
Calculate the solution to these simultaneous equations using the substitution method: (1)(1)2𝑦2y==𝑥+9x+9(2)(2)𝑦−3𝑥y−3x==33
Solution
The language of the text you provided is not clear. However, I can help you solve the simultaneous equations using the substitution method. Here are the steps:
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First, let's rewrite the equations to make them more clear:
Equation 1: 2y = x + 9 Equation 2: y - 3x = 3
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From Equation 1, we can express x in terms of y: x = 2y - 9
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Now, we substitute x = 2y - 9 into Equation 2:
y - 3(2y - 9) = 3 y - 6y + 27 = 3 -5y + 27 = 3 -5y = 3 - 27 -5y = -24 y = -24 / -5 y = 4.8
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Now that we have y, we can substitute y = 4.8 into Equation 1 to find x:
2(4.8) = x + 9 9.6 = x + 9 x = 9.6 - 9 x = 0.6
So, the solution to the simultaneous equations is x = 0.6 and y = 4.8.
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