Calculate the solution to these simultaneous equations using the substitution method: (1)(1)𝑏b==3𝑎+93a+9 (2)(2)𝑏b==𝑎+5a+5
Question
Calculate the solution to these simultaneous equations using the substitution method: (1)(1)𝑏b==3𝑎+93a+9 (2)(2)𝑏b==𝑎+5a+5
Solution
Sure, let's solve these simultaneous equations step by step:
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We have two equations here:
Equation 1: b = 3a + 9 Equation 2: b = a + 5
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Since both equations are equal to b, we can set them equal to each other:
3a + 9 = a + 5
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Now, let's simplify this equation by subtracting 'a' from both sides:
3a - a = 5 - 9 2a = -4
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Finally, let's solve for 'a' by dividing both sides by 2:
a = -4 / 2 a = -2
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Now that we have 'a', we can substitute it into the second equation to find 'b':
b = a + 5 b = -2 + 5 b = 3
So, the solution to the simultaneous equations is a = -2 and b = 3.
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