What is the output for the following code?123456789#include <iostream>int main() { float* ptr = new float(3.14); float* newPtr = ptr; delete ptr; std::cout << *newPtr; return 0;}Marks : 1Negative Marks : 0Answer hereGarbage value0.0Compile Time ErrorNone of the mentioned options
Question
What is the output for the following code?123456789#include <iostream>int main() { float* ptr = new float(3.14); float* newPtr = ptr; delete ptr; std::cout << *newPtr; return 0;}Marks : 1Negative Marks : 0Answer hereGarbage value0.0Compile Time ErrorNone of the mentioned options
Solution
The output of the code will be undefined. This is because after deleting the pointer 'ptr', you are trying to access the memory location it was pointing to using 'newPtr'. This memory location is no longer valid, so it will result in undefined behavior. Therefore, the correct answer is "None of the mentioned options".
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