olve the following system of equations: 2𝑥+4𝑦=16 −3𝑥+3𝑦=−6 𝑥= 𝑦 =
Question
olve the following system of equations: 2𝑥+4𝑦=16 −3𝑥+3𝑦=−6 𝑥= 𝑦 =
Solution
To solve the system of equations:
2x + 4y = 16 -3x + 3y = -6
First, simplify the equations if possible. The first equation can be simplified by dividing the entire equation by 2:
x + 2y = 8
The second equation can be simplified by dividing the entire equation by 3:
-x + y = -2
Now, the system of equations is:
x + 2y = 8 -x + y = -2
Next, add the two equations together:
x + 2y - x + y = 8 - 2 3y = 6
Solve for y by dividing both sides by 3:
y = 2
Substitute y = 2 into the first equation:
x + 2*2 = 8 x + 4 = 8 x = 8 - 4 x = 4
So, the solution to the system of equations is x = 4 and y = 2.
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