If the following registers have the specified values,R0 = 0x00000000R1 = 0x00000005R2 = 0x00000002Then the result of MULL R0, R1, R2 will be ___________ and the result is stored in _______.a.0x00000010 & R0b.0x00000010 & R1c.0x0000000A & R1d.0x0000000A & R0

Given that general purpose register $1 has the value 10 in it, and $2 has the value 6, whichone of the following lines results in the value 26 being stored in $2?a. addi $1, $2, 10b. addi $1, $2, 0x10c. addi $2, $1, 10d. addi $2, $1, 0x10

Consider the instructions in the given figure and find the contents of the CPU registers - PC, MAR, MDR, IR, R1 and R2.

Suppose registers ‘A’ and ‘B’ contain 50H and 40H respectively. After instruction MOV A, B, what will be the contents of registers A and B in 8085 microprocessor?40H, 40H50H, 50H50H, 40H60H, 40H

Assume the following shows the initial contents of the specified registers:REGISTER CONTENTSR1 0000 0000 0000 1001R2 0000 0000 0000 0101R3 0000 0000 0000 0010Also assume the following LC-3 machine instructions are loaded into memory at addresses shown:0x4000 1001 011 010 1 111110x4001 0001 011 011 1 000010x4002 0001 010 001 0 00 0110x4003 0000 001 001100000After the code above completes execution, what is the final value in each register below?(Enter your 16-bit answer in hex like the following example: 0x2A3F)A.)   R1?  B.)   R2?  C.)   R3?  D.)   PC?

Translate the following C code to MIPS assembly code.  Assume that the values of a, b, i, and j are in registers $s0, $s1, $t0, and $t1, respectively. Also, assume that register $s2 holds the base address of the array D and its value is 0x10 (1016). Thus, D[j] contains the value at address 0x10 + 4 * j.for(i=0; i<a; i++)for(j=0; j<b; j++)D[j] = i + j;