Suppose registers ‘A’ and ‘B’ contain 50H and 40H respectively. After instruction MOV A, B, what will be the contents of registers A and B in 8085 microprocessor?40H, 40H50H, 50H50H, 40H60H, 40H
Question
Suppose registers ‘A’ and ‘B’ contain 50H and 40H respectively. After instruction MOV A, B, what will be the contents of registers A and B in 8085 microprocessor?40H, 40H50H, 50H50H, 40H60H, 40H
Solution
The instruction MOV A, B in 8085 microprocessor means "move the contents of register B to register A".
So, before the instruction, we have:
- Register A = 50H
- Register B = 40H
After the instruction MOV A, B, the contents of register B (which is 40H) will be moved to register A. So, we will have:
- Register A = 40H (as it now contains the value from register B)
- Register B = 40H (its content remains unchanged)
So, the contents of registers A and B after the instruction will be 40H, 40H.
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