What is the output of the following code?int arr[5] = {1, 2, 3};printf("%d\n", arr[4]);
Question
What is the output of the following code?int arr[5] = {1, 2, 3};printf("%d\n", arr[4]);
Solution
The output of the code will be 0.
Explanation: In C, when you declare an array and initialize it with fewer elements than the declared size, the remaining elements will be automatically initialized to 0. So, in this case, the array arr[5] will look like this: {1, 2, 3, 0, 0}. Therefore, when you print arr[4], it will output 0.
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