If a = 0.24 & b = 1.76, then compute the following expression.a4 + 4ab3 + 6a2b2 + 4ab3 + b4
Question
If a = 0.24 & b = 1.76, then compute the following expression.a4 + 4ab3 + 6a2b2 + 4ab3 + b4
Solution
Sure, let's break it down:
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Compute a^4: a^4 = (0.24)^4 = 0.0033
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Compute 4ab^3: 4ab^3 = 4 * 0.24 * (1.76)^3 = 3.7687
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Compute 6a^2b^2: 6a^2b^2 = 6 * (0.24)^2 * (1.76)^2 = 1.5094
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Compute 4ab^3 again (since it's repeated in the expression): 4ab^3 = 3.7687 (as computed above)
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Compute b^4: b^4 = (1.76)^4 = 9.6030
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Add all the computed values together: 0.0033 + 3.7687 + 1.5094 + 3.7687 + 9.6030 = 18.6531
So, a^4 + 4ab^3 + 6a^2b^2 + 4ab^3 + b^4 = 18.6531
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