The hybridisation of the central atom in PCl5 can be determined by the following steps:

1. Identify the central atom: In PCl5, the central atom is Phosphorus (P).

2. Count the number of atoms bonded to it (atoms, not bonds!): There are 5 Chlorine (Cl) atoms bonded to the central Phosphorus atom.

3. Count the number of lone pairs on the central atom: Phosphorus does not have any lone pairs in PCl5.

4. Add these two numbers together: 5 (from step 2) + 0 (from step 3) = 5

5. The sum corresponds to the hybridisation state of the atom: 5 corresponds to sp3d.

So, the hybridisation of the central atom in PCl5 is sp3d (option A).

Question

The hybridisation of the central atom in PCl5 can be determined by the following steps:

1. Identify the central atom: In PCl5, the central atom is Phosphorus (P).

2. Count the number of atoms bonded to it (atoms, not bonds!): There are 5 Chlorine (Cl) atoms bonded to the central Phosphorus atom.

3. Count the number of lone pairs on the central atom: Phosphorus does not have any lone pairs in PCl5.

4. Add these two numbers together: 5 (from step 2) + 0 (from step 3) = 5

5. The sum corresponds to the hybridisation state of the atom: 5 corresponds to sp3d.

So, the hybridisation of the central atom in PCl5 is sp3d (option A).

Knowee AI · Accepted Answer

The hybridisation of the central atom in PCl5 can be determined by the following steps:

1. Identify the central atom: In PCl5, the central atom is Phosphorus (P).

2. Count the number of atoms bonded to it (atoms, not bonds!): There are 5 Chlorine (Cl) atoms bonded to the central Phosphorus atom.

3. Count the number of lone pairs on the central atom: Phosphorus does not have any lone pairs in PCl5.

4. Add these two numbers together: 5 (from step 2) + 0 (from step 3) = 5

5. The sum corresponds to the hybridisation state of the atom: 5 corresponds to sp3d.

So, the hybridisation of the central atom in PCl5 is sp3d (option A).

The hybridisation of the central atom in PCl5 is :A sp3d B sp3 C sp D sp2