Solve −5(x+2)+6(x−2)≥10−5(𝑥+2)+6(𝑥−2)≥10.
Question
Solve −5(x+2)+6(x−2)≥10−5(𝑥+2)+6(𝑥−2)≥10.
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Solution
Sure, let's solve the inequality step by step:
−5(x+2)+6(x−2)≥10
First, distribute the -5 and 6 to the terms inside the parentheses:
-5x - 10 + 6x - 12 ≥ 10
Then, combine like terms:
x - 22 ≥ 10
Next, add 22 to both sides of the inequality to isolate x:
x ≥ 10 + 22
So, the solution to the inequality is:
x ≥ 32
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