Solve 2(𝑥−3)≥−3(−3+𝑥)2(x−3)≥−3(−3+x).

Sure, let's solve the inequality step by step:

1. Distribute the numbers outside the parentheses on both sides of the inequality:

   2x - 6 ≥ -3x + 9

2. Next, let's get all the x terms on one side and the numbers on the other side. We can do this by adding 3x to both sides and adding 6 to both sides:

   2x + 3x ≥ -3x + 3x + 9 + 6 5x ≥ 15

3. Finally, divide both sides by 5 to solve for x:

   x ≥ 3

So, the solution to the inequality 2(𝑥−3)≥−3(−3+𝑥) is x ≥ 3.