A semicircular ring of radius 0.5 m is uniformly charged with a total charge of 1.4 ´ 10–9 C. The electric field intensity at the centre of this ring is :–
Question
A semicircular ring of radius 0.5 m is uniformly charged with a total charge of 1.4 ´ 10–9 C. The electric field intensity at the centre of this ring is :–
Solution
The electric field intensity at the center of a uniformly charged semicircular ring can be calculated using the formula:
E = kQ/r^2
where: E is the electric field intensity, k is Coulomb's constant (9 x 10^9 Nm^2/C^2), Q is the total charge on the ring, and r is the radius of the ring.
Given: Q = 1.4 x 10^-9 C, r = 0.5 m.
Substituting these values into the formula, we get:
E = (9 x 10^9 Nm^2/C^2) * (1.4 x 10^-9 C) / (0.5 m)^2 E = 50.4 N/C.
However, this is the electric field intensity for a full circular ring. Since we have a semicircular ring, the electric field intensity will be half of this value.
So, the electric field intensity at the center of the semicircular ring is E = 50.4 N/C / 2 = 25.2 N/C.
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