A non-conducting solid sphere of radius R is uniformly charged. The magnitude of the electric field due to the sphere at a distance r from its centre :-Decreases as r increases, for r < RDecrease as r increase, for 0 < r < ∞Decrease as r increase, for R < r < ∞It discontinuous at r = R
Question
A non-conducting solid sphere of radius R is uniformly charged. The magnitude of the electric field due to the sphere at a distance r from its centre :-Decreases as r increases, for r < RDecrease as r increase, for 0 < r < ∞Decrease as r increase, for R < r < ∞It discontinuous at r = R
Solution
The electric field due to a uniformly charged non-conducting solid sphere can be determined using Gauss's Law. The behavior of the electric field depends on whether the point of interest is inside or outside the sphere.
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For r < R (inside the sphere):
The electric field E inside a uniformly charged non-conducting solid sphere is not zero but varies linearly with distance from the center. It increases as we move from the center towards the surface. Therefore, the electric field decreases as r (distance from the center) increases.
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For r = R (on the surface of the sphere):
The electric field E is maximum at the surface of the sphere. Therefore, it is not discontinuous at r = R.
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For r > R (outside the sphere):
The sphere behaves as a point charge and the electric field E decreases with the square of the distance from the center of the sphere. Therefore, the electric field decreases as r increases for r > R.
So, the correct answer is: The magnitude of the electric field due to the sphere decreases as r increases, for r < R and for R < r < ∞. It is not discontinuous at r = R.
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