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Determine the decimal value of the following Floating point number:11001000101010000000000000000000

Question

Determine the decimal value of the following Floating point number:11001000101010000000000000000000

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Solution 1

The given binary string represents a floating point number in IEEE 754 single-precision format. This format is made up of three parts: the sign bit, the exponent, and the mantissa (or fraction).

  1. Sign bit: The first bit is the sign bit. If the sign bit is 0, the number is positive. If it's 1, the number is negative. In this case, the sign bit is 1, so the number is negative.

  2. Exponent: The next 8 bits are the exponent, expressed as a binary number. In this case, the exponent is 10010001, which is 145 in decimal. However, the IEEE 754 format uses a bias of 127 for the exponent, so we have to subtract 127 from the exponent to get the actual value. So, the actual exponent is 145 - 127 = 18.

  3. Mantissa: The remaining 23 bits are the mantissa. In this case, the mantissa is 01010000000000000000000. To get the value of the mantissa, we place a decimal point after the first bit and read the remaining bits as a binary fraction. So, the mantissa is 0.01010000000000000000000, which is 0.3125 in decimal.

Now, we can put all these parts together to get the value of the floating point number. The formula is (-1)^sign * 1.mantissa * 2^exponent. Plugging in the values we got:

(-1)^1 * 1.3125 * 2^18 = -340,000

So, the decimal value of the floating point number 11001000101010000000000000000000 is -340,000.

This problem has been solved

Solution 2

The given binary string represents a floating point number in IEEE 754 single-precision format. This format is composed of three parts: sign, exponent, and mantissa (or fraction).

  1. Sign: The first bit is the sign bit. If it's 1, the number is negative; if it's 0, the number is positive. In this case, the sign bit is 1, so the number is negative.

  2. Exponent: The next 8 bits represent the exponent, which is biased by 127. In this case, the exponent bits are 10010001, which is 145 in decimal. Subtracting the bias gives us an exponent of 18.

  3. Mantissa: The remaining 23 bits represent the mantissa. In this case, the mantissa bits are 01010000000000000000000.

To find the decimal value, we use the formula (-1)^sign * 1.mantissa * 2^(exponent - 127).

The mantissa in decimal is calculated as follows: 02^-1 + 12^-2 + 02^-3 + 12^-4 + 02^-5 + 02^-6 + 02^-7 + 02^-8 + 02^-9 + 02^-10 + 02^-11 + 02^-12 + 02^-13 + 02^-14 + 02^-15 + 02^-16 + 02^-17 + 02^-18 + 02^-19 + 02^-20 + 02^-21 + 02^-22 + 0*2^-23 = 0.3125

So, the decimal value of the given floating point number is (-1)^1 * 1.3125 * 2^18 = -340,000 approximately.

This problem has been solved

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