In a Young's double slit experiment, the position of the central fringe is determined by the path difference between the two slits. When a slab is placed in front of a slit, it changes the path of light, causing a shift in the fringe pattern. However, if the central fringe remains unaltered, it means that the path difference introduced by the two slabs must be equal.

The path difference introduced by a slab is given by (μ-1)t, where μ is the refractive index of the slab and t is its thickness.

So, for the first slab, the path difference is (1.8-1) * 1.5 mm = 1.2 mm.

Let's denote the thickness of the second slab as t2. The path difference introduced by the second slab is (3.5-1) * t2.

Since the position of the central fringe remains unaltered, the path differences introduced by the two slabs must be equal. Therefore, we have:

1.2 mm = (3.5-1) * t2
1.2 mm = 2.5 * t2
t2 = 1.2 mm / 2.5 = 0.48 mm

So, the thickness of the second slab, t2, is 0.48 mm.

Question

In a Young's double slit experiment, the position of the central fringe is determined by the path difference between the two slits. When a slab is placed in front of a slit, it changes the path of light, causing a shift in the fringe pattern. However, if the central fringe remains unaltered, it means that the path difference introduced by the two slabs must be equal.

The path difference introduced by a slab is given by (μ-1)t, where μ is the refractive index of the slab and t is its thickness.

So, for the first slab, the path difference is (1.8-1) * 1.5 mm = 1.2 mm.

Let's denote the thickness of the second slab as t2. The path difference introduced by the second slab is (3.5-1) * t2.

Since the position of the central fringe remains unaltered, the path differences introduced by the two slabs must be equal. Therefore, we have:

1.2 mm = (3.5-1) * t2
1.2 mm = 2.5 * t2
t2 = 1.2 mm / 2.5 = 0.48 mm

So, the thickness of the second slab, t2, is 0.48 mm.

Knowee AI · Accepted Answer

In a Young's double slit experiment, the position of the central fringe is determined by the path difference between the two slits. When a slab is placed in front of a slit, it changes the path of light, causing a shift in the fringe pattern. However, if the central fringe remains unaltered, it means that the path difference introduced by the two slabs must be equal.

The path difference introduced by a slab is given by (μ-1)t, where μ is the refractive index of the slab and t is its thickness.

So, for the first slab, the path difference is (1.8-1) * 1.5 mm = 1.2 mm.

Let's denote the thickness of the second slab as t2. The path difference introduced by the second slab is (3.5-1) * t2.

Since the position of the central fringe remains unaltered, the path differences introduced by the two slabs must be equal. Therefore, we have:

1.2 mm = (3.5-1) * t2
1.2 mm = 2.5 * t2
t2 = 1.2 mm / 2.5 = 0.48 mm

So, the thickness of the second slab, t2, is 0.48 mm.

In a Young’s double slit experiment, a slab ofthickness t1 = 1.5 mm and refractive index 1.8 isplaced in front of one slit and another slab ofthickness t2 and refractive index 3.5 is placed infront of the second slit. If the position of the centralfringe remains unaltered, then the thickness t2 is

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