A Young's double-slit experiment is performed using monochromatic light of wavelength λλ. The intensity of light at a point on the screen, where the path difference is λλ, is KK units. The intensity of light at a point where the path difference is λ6λ6 is given by nK12nK12, where nn is an integer. The value of nn is
Question
A Young's double-slit experiment is performed using monochromatic light of wavelength λλ. The intensity of light at a point on the screen, where the path difference is λλ, is KK units. The intensity of light at a point where the path difference is λ6λ6 is given by nK12nK12, where nn is an integer. The value of nn is
Solution
In the Young's double-slit experiment, we have monochromatic light with a wavelength of λ.
The intensity of light at a point on the screen, where the path difference is λ, is K units.
Now, let's consider a point where the path difference is λ/6. The intensity of light at this point is given by nK/12, where n is an integer.
To find the value of n, we need to determine the relationship between the path difference and the intensity of light.
From the given information, we can see that the intensity is inversely proportional to the path difference.
Since the path difference is λ/6, the intensity is nK/12.
Therefore, we can conclude that n is equal to 6.
Similar Questions
In a Young’s double slit experiment, the path difference at a certainpoint on the screen between two interfering waves is 𝟏𝟖th of thewavelength. The ratio of intensity at this point to that at the centreof a bright fringe is close to
In Young\'s experiment, monochromatic light is used to illuminate the two slits A and B. Interference fringes are observed on a screen placed in front of the slits. Now if a thin glass plate is placed normally in the path of the beam coming from the slit
In a Young's double slit experiment the separation of the slits is 0.23 mm. The distance to the screen is 1.12 m. The third bright fringe is a distance of 5.9 mm from the central fringe. Determine the wavelength of the light.
5. A single slit of width 0.05 mm is illuminated with monochromatic light of wavelength 500nm. Calculate the intensity of light at an angle of 20∘ relative to the central maximum on a distant screen.
One of Mr. Chowder's lab groups is staying after school to complete the Young's Experiment investigation. They observe that light through passing two slits travels 3.93 m to a screen to produce a pattern of bright and dark bands. The group measures the distance between the first and the second bright bands on the same side of the pattern to be 18.8 mm. The slits are spaced 0.132 mm apart. What is the wavelength (in nanometers) of the light source?Wavelengthnm
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.