Let's denote the initial speed of the cyclist as 'x' kmph.

The distance covered by the cyclist is the same in both cases.

We know that distance = speed * time.

So, for the first case, the distance = x * 6.

For the second case, the cyclist increases his speed by 2 kmph, so the speed becomes (x+2) kmph. The distance = (x+2) * 5.

Since the distances in both cases are the same, we can set up the following equation:

x * 6 = (x+2) * 5

Solving this equation will give us the initial speed of the cyclist.

First, distribute on the right side of the equation:

6x = 5x + 10

Then, subtract 5x from both sides:

x = 10

So, the initial speed of the cyclist was 10 kmph.

Question

Let's denote the initial speed of the cyclist as 'x' kmph.

The distance covered by the cyclist is the same in both cases.

We know that distance = speed * time.

So, for the first case, the distance = x * 6.

For the second case, the cyclist increases his speed by 2 kmph, so the speed becomes (x+2) kmph. The distance = (x+2) * 5.

Since the distances in both cases are the same, we can set up the following equation:

x * 6 = (x+2) * 5

Solving this equation will give us the initial speed of the cyclist.

First, distribute on the right side of the equation:

6x = 5x + 10

Then, subtract 5x from both sides:

x = 10

So, the initial speed of the cyclist was 10 kmph.

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