The central Xe atom in the XeF4 molecule has ________ unbonded electron pair(s) and ________ bonded electron pair(s) in its valence shell.  1, 4   2, 4   4, 0   4, 1   4, 2

The central Xe atom in the XeF4 molecule has 2 unbonded electron pair(s) and 4 bonded electron pair(s) in its valence shell.

Here's the step by step explanation:

1. Xenon (Xe) is in Group 8 of the periodic table and therefore has 8 electrons in its outer shell.

2. In the XeF4 molecule, Xenon (Xe) forms four bonds with four Fluorine (F) atoms. This means that 4 out of 8 valence electrons of Xenon are involved in bonding, forming 4 bonded pairs.

3. The remaining 4 electrons stay as non-bonding pairs. However, due to the 'octet rule' which states that elements tend to combine in such a way that they each have eight electrons in their valence shells, only 2 pairs (or 4 electrons) are considered as non-bonding or unbonded pairs.

So, the answer is 2 unbonded electron pairs and 4 bonded electron pairs.