Assuming you are using SQL, here is a step-by-step guide on how to write the query:

1. First, you need to select the column you are interested in, which is the name of the building types. In SQL, you use the SELECT statement for this. If the column name is "building_type", the beginning of your query will look like this: `SELECT building_type`.

2. Next, you want to specify that you're only interested in building types that end with the letter 'l'. For this, you use the WHERE clause in combination with the LIKE keyword. The '%' symbol is used as a wildcard in SQL, meaning it can represent any number of characters. So, to specify that the building type should end with 'l', you add `WHERE building_type LIKE '%l'` to your query.

3. Finally, you want to order the results in ascending order based on the name. For this, you use the ORDER BY clause. To specify ascending order, you use the ASC keyword. So, you add `ORDER BY building_type ASC` to your query.

Putting it all together, your final query will look like this:

```sql
SELECT building_type
FROM your_table
WHERE building_type LIKE '%l'
ORDER BY building_type ASC;
```

Please replace "your_table" with the actual name of your table.

Question

Assuming you are using SQL, here is a step-by-step guide on how to write the query:

1. First, you need to select the column you are interested in, which is the name of the building types. In SQL, you use the SELECT statement for this. If the column name is "building_type", the beginning of your query will look like this: `SELECT building_type`.

2. Next, you want to specify that you're only interested in building types that end with the letter 'l'. For this, you use the WHERE clause in combination with the LIKE keyword. The '%' symbol is used as a wildcard in SQL, meaning it can represent any number of characters. So, to specify that the building type should end with 'l', you add `WHERE building_type LIKE '%l'` to your query.

3. Finally, you want to order the results in ascending order based on the name. For this, you use the ORDER BY clause. To specify ascending order, you use the ASC keyword. So, you add `ORDER BY building_type ASC` to your query.

Putting it all together, your final query will look like this:

```sql
SELECT building_type
FROM your_table
WHERE building_type LIKE '%l'
ORDER BY building_type ASC;
```

Please replace "your_table" with the actual name of your table.

Knowee AI · Accepted Answer

Assuming you are using SQL, here is a step-by-step guide on how to write the query:

1. First, you need to select the column you are interested in, which is the name of the building types. In SQL, you use the SELECT statement for this. If the column name is "building_type", the beginning of your query will look like this: `SELECT building_type`.

2. Next, you want to specify that you're only interested in building types that end with the letter 'l'. For this, you use the WHERE clause in combination with the LIKE keyword. The '%' symbol is used as a wildcard in SQL, meaning it can represent any number of characters. So, to specify that the building type should end with 'l', you add `WHERE building_type LIKE '%l'` to your query.

3. Finally, you want to order the results in ascending order based on the name. For this, you use the ORDER BY clause. To specify ascending order, you use the ASC keyword. So, you add `ORDER BY building_type ASC` to your query.

Putting it all together, your final query will look like this:

```sql
SELECT building_type
FROM your_table
WHERE building_type LIKE '%l'
ORDER BY building_type ASC;
```

Please replace "your_table" with the actual name of your table.

Write a query to display the name of all building types that ends with letter 'l'. Display the records in ascending order based on name

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