To answer this question, we will use SQL (Structured Query Language), which is a standard language for managing data held in a relational database management system.

Here is the SQL query:

```sql
SELECT bt.building_type AS building_name, COUNT(b.building_id) AS number_of_buildings
FROM building_type bt
JOIN building b ON bt.building_type_id = b.building_type_id
GROUP BY bt.building_type
HAVING COUNT(b.building_id) = (
SELECT MAX(building_count)
FROM (
SELECT COUNT(building_id) AS building_count
FROM building
GROUP BY building_type_id
) AS subquery
)
ORDER BY building_name ASC;
```

Let's break down this query:

1. We are joining the `building_type` table (aliased as `bt`) and the `building` table (aliased as `b`) on the `building_type_id` field which is common in both tables.

2. We are grouping the results by the `building_type` field from the `building_type` table.

3. We are counting the number of `building_id` from the `building` table for each `building_type`. This gives us the number of buildings for each type.

4. We are only interested in the building types that have the maximum number of buildings. To find this, we use a subquery that counts the number of buildings for each building type, and then selects the maximum count.

5. Finally, we order the results by the `building_name` in ascending order.

Question

To answer this question, we will use SQL (Structured Query Language), which is a standard language for managing data held in a relational database management system.

Here is the SQL query:

```sql
SELECT bt.building_type AS building_name, COUNT(b.building_id) AS number_of_buildings
FROM building_type bt
JOIN building b ON bt.building_type_id = b.building_type_id
GROUP BY bt.building_type
HAVING COUNT(b.building_id) = (
  SELECT MAX(building_count)
  FROM (
    SELECT COUNT(building_id) AS building_count
    FROM building
    GROUP BY building_type_id
  ) AS subquery
)
ORDER BY building_name ASC;
```

Let's break down this query:

1. We are joining the `building_type` table (aliased as `bt`) and the `building` table (aliased as `b`) on the `building_type_id` field which is common in both tables.

2. We are grouping the results by the `building_type` field from the `building_type` table.

3. We are counting the number of `building_id` from the `building` table for each `building_type`. This gives us the number of buildings for each type.

4. We are only interested in the building types that have the maximum number of buildings. To find this, we use a subquery that counts the number of buildings for each building type, and then selects the maximum count.

5. Finally, we order the results by the `building_name` in ascending order.

Knowee AI · Accepted Answer

To answer this question, we will use SQL (Structured Query Language), which is a standard language for managing data held in a relational database management system.

Here is the SQL query:

```sql
SELECT bt.building_type AS building_name, COUNT(b.building_id) AS number_of_buildings
FROM building_type bt
JOIN building b ON bt.building_type_id = b.building_type_id
GROUP BY bt.building_type
HAVING COUNT(b.building_id) = (
  SELECT MAX(building_count)
  FROM (
    SELECT COUNT(building_id) AS building_count
    FROM building
    GROUP BY building_type_id
  ) AS subquery
)
ORDER BY building_name ASC;
```

Let's break down this query:

1. We are joining the `building_type` table (aliased as `bt`) and the `building` table (aliased as `b`) on the `building_type_id` field which is common in both tables.

2. We are grouping the results by the `building_type` field from the `building_type` table.

3. We are counting the number of `building_id` from the `building` table for each `building_type`. This gives us the number of buildings for each type.

4. We are only interested in the building types that have the maximum number of buildings. To find this, we use a subquery that counts the number of buildings for each building type, and then selects the maximum count.

5. Finally, we order the results by the `building_name` in ascending order.

Question

Solution

Similar Questions

Upgrade your grade with Knowee