What will be the output of the following Python code?def foo(): total += 1 return totaltotal = 0print(foo())

The code will raise an UnboundLocalError. This is because the variable 'total' is not defined in the local scope of the function 'foo'.

Here's a step-by-step explanation:

1. The variable 'total' is defined in the global scope and is set to 0.

2. The function 'foo' is defined. Inside this function, it tries to increment the value of 'total' by 1. However, 'total' is not defined in the local scope of 'foo'.

3. When 'foo' is called in the print statement, Python looks for a local variable 'total'. It doesn't find one, so it raises an UnboundLocalError.

To fix this error, you can use the 'global' keyword to tell Python that 'total' is a global variable:

def foo():
    global total
    total += 1
    return total

total = 0
print(foo())

This will output: 1