Statement I: A body is thrown verticallyupwards. If air resistance is to be takeninto account, then the time duringwhich the body rises is greater than thetime of fall.Statement II: A body is thrown verticallyupwards and when it reaches half of itsmaximum height, its accelerationremains same
Question
Statement I: A body is thrown verticallyupwards. If air resistance is to be takeninto account, then the time duringwhich the body rises is greater than thetime of fall.Statement II: A body is thrown verticallyupwards and when it reaches half of itsmaximum height, its accelerationremains same
Solution
Statement I: When a body is thrown vertically upwards, it experiences a force of gravity pulling it downwards and air resistance pushing it upwards. This means that the body will take longer to reach its peak height than it would if there was no air resistance. On the other hand, when the body is falling, both gravity and air resistance are acting in the same direction (downwards), so the body falls faster than it rose. Therefore, the time during which the body rises is greater than the time of fall.
Statement II: The acceleration of a body thrown vertically upwards is always the same, regardless of its position. This is because the acceleration is due to gravity, which is a constant force. Even when the body reaches half of its maximum height, the acceleration remains the same. However, the velocity of the body decreases as it rises due to the opposing force of gravity.
Similar Questions
A ball is thrown vertically upwards. Assuming the air resistance to be constant and considerable :–the time of ascent ≥ the time of descentthe time of ascent < the time of descentthe time of ascent > the time of descentthe time of ascent = the time of descent
A body released from rest falls with an acceleration of 9.81 m/s2. If the same body is thrown upward, and air resistance is negligible, its acceleration will be Question 11Answera.upward and greater than 9.81 m/s2b.downward and greater than 9.81 m/s2c.downward and less than 9.81 m/s2d.upward and equal to 9.81 m/s2e.downward and equal to 9.81 m/s2
Statement – I: If a body is thrown upwards, the distance covered by it in the last second of upward motion is independent upon its initial speed.Statement – II: The distance covered in the last second of upward motion is equal to that covered in the first second of downward motion when the particle is dropped.
A body is thrown upwards with speed u from a building of height h. Another body B is thrown downwards with speed u. They reach ground with speed and respectively. The relation between and .
An object is thrown vertically upwards with an initial velocity of m/s. (take g=10m/s2 Find –(innotebook)-(i) time taken to reach maximum height(ii) maximum height reached(iii) velocity after 5 seconds
Upgrade your grade with Knowee
Get personalized homework help. Review tough concepts in more detail, or go deeper into your topic by exploring other relevant questions.