Statement – I: If a body is thrown upwards, the distance covered by it in the last second of upward motion is independent upon its initial speed.Statement – II: The distance covered in the last second of upward motion is equal to that covered in the first second of downward motion when the particle is dropped.
Question
Statement – I: If a body is thrown upwards, the distance covered by it in the last second of upward motion is independent upon its initial speed.Statement – II: The distance covered in the last second of upward motion is equal to that covered in the first second of downward motion when the particle is dropped.
Solution
Statement I: This statement is true. When a body is thrown upwards, it decelerates due to gravity. In the last second of its upward motion, it covers a distance of approximately 4.9 meters (assuming the acceleration due to gravity is -9.8 m/s²), regardless of its initial speed. This is because in the last second of upward motion, the body is essentially 'falling' upwards against gravity.
Statement II: This statement is also true. The distance covered in the last second of upward motion is indeed equal to the distance covered in the first second of downward motion. This is because the body starts from rest in both cases (at the highest point of upward motion and at the start of downward motion) and is subject to the same acceleration due to gravity. Therefore, it covers the same distance, approximately 4.9 meters, in both cases.
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