If the random variable X assumes the values 0 and 1 only and is such that P(X = 0) = 3P(X = 1), then the value of E(X) is
Question
If the random variable X assumes the values 0 and 1 only and is such that P(X = 0) = 3P(X = 1), then the value of E(X) is
Solution
The expected value E(X) of a random variable X is calculated as the sum of all possible values of X multiplied by their respective probabilities.
Given that X can take on the values 0 and 1 only, and that P(X = 0) = 3P(X = 1), we can first find the probability P(X = 1).
Let's denote P(X = 1) as p. Then P(X = 0) = 3p.
Since the sum of all probabilities must equal 1, we have:
p + 3p = 1 4p = 1 p = 1/4
Therefore, P(X = 1) = 1/4 and P(X = 0) = 3/4.
Now we can calculate the expected value E(X):
E(X) = 0P(X = 0) + 1P(X = 1) = 0*(3/4) + 1*(1/4) = 0 + 1/4 = 1/4
So, the expected value E(X) is 1/4.
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