Let X be a random variable with probability mass functionx -3 6 9pX (x) 1/6 1/2 1/3Find E(X), E(X2) and E(2X + 1)2

f the random variable X assumes the values 0 and 1 only and is such that P(X = 0) = 3P(X = 1), then the value of E(X) isans.

If the random variable X assumes the values 0 and 1 only and is such that P(X = 0) = 3P(X = 1), then the value of E(X) is ans. 1/3 1/4 2/3 none

If the random variable X assumes the values 0 and 1 only and is such that P(X = 0) = 3P(X =

Suppose X is a random variable with possible outcomes 0 and 2, with P( X = 2 ) = 0.3. The variance of X is

Distribution function of a random variable X is given by F(x) = 1 - 1/(x ^ 2); 1 <= x < ∞ Then P(X <= 2) and respectively P(X > 3/2) are