A cereal company estimates that its monthly cost is ๐ถ(๐ฅ)=400๐ฅ2+300๐ฅC(x)=400x 2 +300x and its monthly revenue is ๐ (๐ฅ)=โ0.6๐ฅ3+900๐ฅ2โ400๐ฅ+700R(x)=โ0.6x 3 +900x 2 โ400x+700, where x is in thousands of boxes sold. The profit is the difference between the revenue and the cost.What is the profit function, P(x)?A.๐(๐ฅ)=0.6๐ฅ3โ500๐ฅ2+700๐ฅโ700P(x)=0.6x 3 โ500x 2 +700xโ700B.๐(๐ฅ)=0.6๐ฅ3โ1300๐ฅ2+100๐ฅ+700P(x)=0.6x 3 โ1300x 2 +100x+700C.๐(๐ฅ)=โ0.6๐ฅ3+1300๐ฅ2โ100๐ฅ+700P(x)=โ0.6x 3 +1300x 2 โ100x+700D.๐(๐ฅ)=โ0.6๐ฅ3+500๐ฅ2โ700๐ฅ+700P(x)=โ0.6x 3 +500x 2 โ700x+700SUBMITarrow_backPREVIOUS
Question
A cereal company estimates that its monthly cost is ๐ถ(๐ฅ)=400๐ฅ2+300๐ฅC(x)=400x 2 +300x and its monthly revenue is ๐ (๐ฅ)=โ0.6๐ฅ3+900๐ฅ2โ400๐ฅ+700R(x)=โ0.6x 3 +900x 2 โ400x+700, where x is in thousands of boxes sold. The profit is the difference between the revenue and the cost.What is the profit function, P(x)?A.๐(๐ฅ)=0.6๐ฅ3โ500๐ฅ2+700๐ฅโ700P(x)=0.6x 3 โ500x 2 +700xโ700B.๐(๐ฅ)=0.6๐ฅ3โ1300๐ฅ2+100๐ฅ+700P(x)=0.6x 3 โ1300x 2 +100x+700C.๐(๐ฅ)=โ0.6๐ฅ3+1300๐ฅ2โ100๐ฅ+700P(x)=โ0.6x 3 +1300x 2 โ100x+700D.๐(๐ฅ)=โ0.6๐ฅ3+500๐ฅ2โ700๐ฅ+700P(x)=โ0.6x 3 +500x 2 โ700x+700SUBMITarrow_backPREVIOUS
Solution
The profit function, P(x), is found by subtracting the cost function, C(x), from the revenue function, R(x). This means we have:
P(x) = R(x) - C(x)
Substituting the given functions into this equation gives:
P(x) = (-0.6x^3 + 900x^2 - 400x + 700) - (400x^2 + 300x)
Simplify the equation by combining like terms:
P(x) = -0.6x^3 + (900x^2 - 400x^2) - (400x - 300x) + 700 P(x) = -0.6x^3 + 500x^2 - 100x + 700
So, the profit function is P(x) = -0.6x^3 + 500x^2 - 100x + 700, which corresponds to option D.
Similar Questions
Suppose a granola bar company estimates that its monthly cost is ๐ถ(๐ฅ)=500๐ฅ2+400๐ฅC(x)=500x 2 +400x and its monthly revenue is ๐ (๐ฅ)=โ0.6๐ฅ3+800๐ฅ2โ300๐ฅ+600R(x)=โ0.6x 3 +800x 2 โ300x+600, where x is in thousands of granola bars sold. The profit is the difference between the revenue and the cost.What is the profit function, P(x)?A.๐(๐ฅ)=โ0.6๐ฅ3+1300๐ฅ2+100๐ฅ+600P(x)=โ0.6x 3 +1300x 2 +100x+600B.๐(๐ฅ)=0.6๐ฅ3+300๐ฅ2โ700๐ฅ+600P(x)=0.6x 3 +300x 2 โ700x+600C.๐(๐ฅ)=โ0.6๐ฅ3+300๐ฅ2โ700๐ฅ+600P(x)=โ0.6x 3 +300x 2 โ700x+600D.๐(๐ฅ)=0.6๐ฅ3โ300๐ฅ2+700๐ฅโ600P(x)=0.6x 3 โ300x 2 +700xโ600SUBMITarrow_backPREVIOUS
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