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A cereal company estimates that its monthly cost is ๐ถ(๐‘ฅ)=400๐‘ฅ2+300๐‘ฅC(x)=400x 2 +300x and its monthly revenue is ๐‘…(๐‘ฅ)=โˆ’0.6๐‘ฅ3+900๐‘ฅ2โˆ’400๐‘ฅ+700R(x)=โˆ’0.6x 3 +900x 2 โˆ’400x+700, where x is in thousands of boxes sold. The profit is the difference between the revenue and the cost.What is the profit function, P(x)?A.๐‘ƒ(๐‘ฅ)=0.6๐‘ฅ3โˆ’500๐‘ฅ2+700๐‘ฅโˆ’700P(x)=0.6x 3 โˆ’500x 2 +700xโˆ’700B.๐‘ƒ(๐‘ฅ)=0.6๐‘ฅ3โˆ’1300๐‘ฅ2+100๐‘ฅ+700P(x)=0.6x 3 โˆ’1300x 2 +100x+700C.๐‘ƒ(๐‘ฅ)=โˆ’0.6๐‘ฅ3+1300๐‘ฅ2โˆ’100๐‘ฅ+700P(x)=โˆ’0.6x 3 +1300x 2 โˆ’100x+700D.๐‘ƒ(๐‘ฅ)=โˆ’0.6๐‘ฅ3+500๐‘ฅ2โˆ’700๐‘ฅ+700P(x)=โˆ’0.6x 3 +500x 2 โˆ’700x+700SUBMITarrow_backPREVIOUS

Question

A cereal company estimates that its monthly cost is ๐ถ(๐‘ฅ)=400๐‘ฅ2+300๐‘ฅC(x)=400x 2 +300x and its monthly revenue is ๐‘…(๐‘ฅ)=โˆ’0.6๐‘ฅ3+900๐‘ฅ2โˆ’400๐‘ฅ+700R(x)=โˆ’0.6x 3 +900x 2 โˆ’400x+700, where x is in thousands of boxes sold. The profit is the difference between the revenue and the cost.What is the profit function, P(x)?A.๐‘ƒ(๐‘ฅ)=0.6๐‘ฅ3โˆ’500๐‘ฅ2+700๐‘ฅโˆ’700P(x)=0.6x 3 โˆ’500x 2 +700xโˆ’700B.๐‘ƒ(๐‘ฅ)=0.6๐‘ฅ3โˆ’1300๐‘ฅ2+100๐‘ฅ+700P(x)=0.6x 3 โˆ’1300x 2 +100x+700C.๐‘ƒ(๐‘ฅ)=โˆ’0.6๐‘ฅ3+1300๐‘ฅ2โˆ’100๐‘ฅ+700P(x)=โˆ’0.6x 3 +1300x 2 โˆ’100x+700D.๐‘ƒ(๐‘ฅ)=โˆ’0.6๐‘ฅ3+500๐‘ฅ2โˆ’700๐‘ฅ+700P(x)=โˆ’0.6x 3 +500x 2 โˆ’700x+700SUBMITarrow_backPREVIOUS

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Solution

The profit function, P(x), is found by subtracting the cost function, C(x), from the revenue function, R(x). This means we have:

P(x) = R(x) - C(x)

Substituting the given functions into this equation gives:

P(x) = (-0.6x^3 + 900x^2 - 400x + 700) - (400x^2 + 300x)

Simplify the equation by combining like terms:

P(x) = -0.6x^3 + (900x^2 - 400x^2) - (400x - 300x) + 700 P(x) = -0.6x^3 + 500x^2 - 100x + 700

So, the profit function is P(x) = -0.6x^3 + 500x^2 - 100x + 700, which corresponds to option D.

This problem has been solved

Similar Questions

Suppose a granola bar company estimates that its monthly cost is ๐ถ(๐‘ฅ)=500๐‘ฅ2+400๐‘ฅC(x)=500x 2 +400x and its monthly revenue is ๐‘…(๐‘ฅ)=โˆ’0.6๐‘ฅ3+800๐‘ฅ2โˆ’300๐‘ฅ+600R(x)=โˆ’0.6x 3 +800x 2 โˆ’300x+600, where x is in thousands of granola bars sold. The profit is the difference between the revenue and the cost.What is the profit function, P(x)?A.๐‘ƒ(๐‘ฅ)=โˆ’0.6๐‘ฅ3+1300๐‘ฅ2+100๐‘ฅ+600P(x)=โˆ’0.6x 3 +1300x 2 +100x+600B.๐‘ƒ(๐‘ฅ)=0.6๐‘ฅ3+300๐‘ฅ2โˆ’700๐‘ฅ+600P(x)=0.6x 3 +300x 2 โˆ’700x+600C.๐‘ƒ(๐‘ฅ)=โˆ’0.6๐‘ฅ3+300๐‘ฅ2โˆ’700๐‘ฅ+600P(x)=โˆ’0.6x 3 +300x 2 โˆ’700x+600D.๐‘ƒ(๐‘ฅ)=0.6๐‘ฅ3โˆ’300๐‘ฅ2+700๐‘ฅโˆ’600P(x)=0.6x 3 โˆ’300x 2 +700xโˆ’600SUBMITarrow_backPREVIOUS

Determine the total profit function, P(x)

The organizer of a sports event estimates that if the event is announced ๐‘ฅ days in advance, the revenueobtained will be ๐‘…(๐‘ฅ) thousand dollars, where๐‘…(๐‘ฅ) = 400 + 120๐‘ฅ โˆ’ ๐‘ฅ2The cost of advertising the event for ๐‘ฅ days is ๐ถ(๐‘ฅ) = 2๐‘ฅ2 + 300a. Find the profit function ๐‘ƒ(๐‘ฅ) = ๐‘…(๐‘ฅ) โˆ’ ๐ถ(๐‘ฅ) and sketch its graph.b. How many days in advance should the event be announced in order to maximize profit? What is themaximum profit?c. What is the ratio of revenue to cost ๐‘„(๐‘ฅ) = ๐‘…(๐‘ฅ)๐ถ(๐‘ฅ) at the optimal announcement time found in part (b)?What happens to this ratio as ๐‘ฅ โ†’ 0? Interpret these results

The cost for a company to produce x smartphones can be modeled by C(๐‘ฅ)=2๐‘ฅ+35C(x)=2x+35 and the company's total profit after selling x smartphones can be modeled by P(x) = -x2 + 120x - 435. Which function represents the company's revenue for selling smartphones? (Recall that profit equals revenue minus cost.)A.R(๐‘ฅ)=โˆ’๐‘ฅ2+118๐‘ฅโˆ’470R(x)=โˆ’x 2 +118xโˆ’470B.R(๐‘ฅ)=โˆ’๐‘ฅ2+122๐‘ฅ+400R(x)=โˆ’x 2 +122x+400C.R(๐‘ฅ)=โˆ’๐‘ฅ2+122๐‘ฅโˆ’470R(x)=โˆ’x 2 +122xโˆ’470D.R(๐‘ฅ)=โˆ’๐‘ฅ2+122๐‘ฅโˆ’400R(x)=โˆ’x 2 +122xโˆ’400SUBMITarrow_backPREVIOUS

The total cost (in dollars) for a company to manufacture and sell ๐‘ฅ items per week is ๐ถ=50โข๐‘ฅ+2960, whereas the revenue brought in by selling all ๐‘ฅ items is ๐‘…=140โข๐‘ฅ-0.6โข๐‘ฅ2. How many items must be sold to obtain a weekly profit of $400?Hint: Profit = Revenue - Cost.They need to sell or items.

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