Suppose a granola bar company estimates that its monthly cost is ๐ถ(๐ฅ)=500๐ฅ2+400๐ฅC(x)=500x 2 +400x and its monthly revenue is ๐ (๐ฅ)=โ0.6๐ฅ3+800๐ฅ2โ300๐ฅ+600R(x)=โ0.6x 3 +800x 2 โ300x+600, where x is in thousands of granola bars sold. The profit is the difference between the revenue and the cost.What is the profit function, P(x)?A.๐(๐ฅ)=โ0.6๐ฅ3+1300๐ฅ2+100๐ฅ+600P(x)=โ0.6x 3 +1300x 2 +100x+600B.๐(๐ฅ)=0.6๐ฅ3+300๐ฅ2โ700๐ฅ+600P(x)=0.6x 3 +300x 2 โ700x+600C.๐(๐ฅ)=โ0.6๐ฅ3+300๐ฅ2โ700๐ฅ+600P(x)=โ0.6x 3 +300x 2 โ700x+600D.๐(๐ฅ)=0.6๐ฅ3โ300๐ฅ2+700๐ฅโ600P(x)=0.6x 3 โ300x 2 +700xโ600SUBMITarrow_backPREVIOUS
Question
Suppose a granola bar company estimates that its monthly cost is ๐ถ(๐ฅ)=500๐ฅ2+400๐ฅC(x)=500x 2 +400x and its monthly revenue is ๐ (๐ฅ)=โ0.6๐ฅ3+800๐ฅ2โ300๐ฅ+600R(x)=โ0.6x 3 +800x 2 โ300x+600, where x is in thousands of granola bars sold. The profit is the difference between the revenue and the cost.What is the profit function, P(x)?A.๐(๐ฅ)=โ0.6๐ฅ3+1300๐ฅ2+100๐ฅ+600P(x)=โ0.6x 3 +1300x 2 +100x+600B.๐(๐ฅ)=0.6๐ฅ3+300๐ฅ2โ700๐ฅ+600P(x)=0.6x 3 +300x 2 โ700x+600C.๐(๐ฅ)=โ0.6๐ฅ3+300๐ฅ2โ700๐ฅ+600P(x)=โ0.6x 3 +300x 2 โ700x+600D.๐(๐ฅ)=0.6๐ฅ3โ300๐ฅ2+700๐ฅโ600P(x)=0.6x 3 โ300x 2 +700xโ600SUBMITarrow_backPREVIOUS
Solution
The profit function, P(x), is found by subtracting the cost function, C(x), from the revenue function, R(x). This means we have:
P(x) = R(x) - C(x)
Substituting the given functions into this equation gives:
P(x) = (-0.6x^3 + 800x^2 - 300x + 600) - (500x^2 + 400x)
Simplify this by combining like terms:
P(x) = -0.6x^3 + (800x^2 - 500x^2) + (-300x - 400x) + 600 P(x) = -0.6x^3 + 300x^2 - 700x + 600
So, the correct answer is C. ๐(๐ฅ)=โ0.6๐ฅ3+300๐ฅ2โ700๐ฅ+600.
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The cost for a company to produce x smartphones can be modeled by C(๐ฅ)=2๐ฅ+35C(x)=2x+35 and the company's total profit after selling x smartphones can be modeled by P(x) = -x2 + 120x - 435. Which function represents the company's revenue for selling smartphones? (Recall that profit equals revenue minus cost.)A.R(๐ฅ)=โ๐ฅ2+118๐ฅโ470R(x)=โx 2 +118xโ470B.R(๐ฅ)=โ๐ฅ2+122๐ฅ+400R(x)=โx 2 +122x+400C.R(๐ฅ)=โ๐ฅ2+122๐ฅโ470R(x)=โx 2 +122xโ470D.R(๐ฅ)=โ๐ฅ2+122๐ฅโ400R(x)=โx 2 +122xโ400SUBMITarrow_backPREVIOUS
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The demand function of a product for a manufacturer is ๐ (๐ฅ) = ๐๐ฅ + ๐. The manufacturer knows that he can sell 1250 units when the price is GHS5 per unit and he can sell 1500 units at a price of GHS4 per unit. Find the total, and average revenue functions.
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