The demand function of a product for a manufacturer is ๐ (๐ฅ) = ๐๐ฅ + ๐. The manufacturer knows that he can sell 1250 units when the price is GHS5 per unit and he can sell 1500 units at a price of GHS4 per unit. Find the total, and average revenue functions.
Question
The demand function of a product for a manufacturer is ๐ (๐ฅ) = ๐๐ฅ + ๐. The manufacturer knows that he can sell 1250 units when the price is GHS5 per unit and he can sell 1500 units at a price of GHS4 per unit. Find the total, and average revenue functions.
Solution
To find the total and average revenue functions, we first need to find the values of a and b in the demand function p(x) = ax + b.
Step 1: Substitute the given values into the demand function
We know that when the price is GHS5, 1250 units are sold. So, we substitute p = 5 and x = 1250 into the demand function:
5 = 1250a + b ----(equation 1)
We also know that when the price is GHS4, 1500 units are sold. So, we substitute p = 4 and x = 1500 into the demand function:
4 = 1500a + b ----(equation 2)
Step 2: Solve the system of equations to find a and b
Subtract equation 2 from equation 1:
5 - 4 = 1250a - 1500a + b - b
1 = -250a
So, a = -1/250 = -0.004
Substitute a = -0.004 into equation 1:
5 = 1250(-0.004) + b
5 = -5 + b
So, b = 10
So, the demand function is p(x) = -0.004x + 10
Step 3: Find the total revenue function
The total revenue (R) is the product of the price (p) and the quantity (x), so R(x) = p(x) * x
Substitute p(x) = -0.004x + 10 into the equation:
R(x) = (-0.004x + 10) * x = -0.004x^2 + 10x
Step 4: Find the average revenue function
The average revenue (AR) is the total revenue (R) divided by the quantity (x), so AR(x) = R(x) / x
Substitute R(x) = -0.004x^2 + 10x into the equation:
AR(x) = (-0.004x^2 + 10x) / x = -0.004x + 10
So, the total revenue function is R(x) = -0.004x^2 + 10x and the average revenue function is AR(x) = -0.004x + 10.
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